What are the solutions to the equation x^2-20x+19=0 ?

The solutions to the equation x^2-20x+19=0 are x=19,x=1

Find the zeros of x^2-20x+19=0

The zeros of x^2-20x+19=0 are x=19,x=1

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x^{2} - 20 x + 19 = 0

x = 19, x = 1

Solution steps

x^{2} - 20 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 19 = 18

x_{1, 2} = \frac{- ( - 20 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 18}{2 \cdot 1}

x = \frac{- ( - 20 ) + 18}{2 \cdot 1} : 19

x = \frac{- ( - 20 ) - 18}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 19, x = 1

x^{2} - 10 x + 25 = 4

3 x + 4 = x + 10

2 x^{2} - 7 x = 1

- x^{2} - 10 x - 26 \leq - 5

\frac{4 a b ^{- 2}}{- 3 c ^{- 2}}

What are the solutions to the equation x^2-20x+19=0 ?
The solutions to the equation x^2-20x+19=0 are x=19,x=1
Find the zeros of x^2-20x+19=0
The zeros of x^2-20x+19=0 are x=19,x=1