What are the solutions to the equation x^2=6-x ?

The solutions to the equation x^2=6-x are x=2,x=-3

Find the zeros of x^2=6-x

The zeros of x^2=6-x are x=2,x=-3

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x^{2} = 6 - x

x = 2, x = - 3

Solution steps

x^{2} = 6 - x

Move

x

to the left side

x^{2} + x = 6

Move

6

to the left side

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

4 x^{2} - 16 x + 7 = 0

5 x^{2} + 3 x + 5 = 0

5 x^{2} + 10 x

1 - a^{2}

s^{2} - 7 s + 12 = 0

What are the solutions to the equation x^2=6-x ?
The solutions to the equation x^2=6-x are x=2,x=-3
Find the zeros of x^2=6-x
The zeros of x^2=6-x are x=2,x=-3