What are the solutions to the equation 2x^2+13x-24=0 ?

The solutions to the equation 2x^2+13x-24=0 are x= 3/2 ,x=-8

Find the zeros of 2x^2+13x-24=0

The zeros of 2x^2+13x-24=0 are x= 3/2 ,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 13 x - 24 = 0

x = \frac{3}{2}, x = - 8

Decimal Notation

x = 1.5, x = - 8

Solution steps

2 x^{2} + 13 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 24) = 19

x_{1, 2} = \frac{- 13 \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 19}{2 \cdot 2}, x_{2} = \frac{- 13 - 19}{2 \cdot 2}

x = \frac{- 13 + 19}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 13 - 19}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 8

x^{2} - 15 x + 50 = 0

4 + 2 d = 8

16 y x^{4} + 12 y^{3} x^{2} - 20 y x

∣ w ∣ = 0

(x + 3)^{3}

What are the solutions to the equation 2x^2+13x-24=0 ?
The solutions to the equation 2x^2+13x-24=0 are x= 3/2 ,x=-8
Find the zeros of 2x^2+13x-24=0
The zeros of 2x^2+13x-24=0 are x= 3/2 ,x=-8