What are the solutions to the equation 8x^2+12=7x^2+7x ?

The solutions to the equation 8x^2+12=7x^2+7x are x=4,x=3

Find the zeros of 8x^2+12=7x^2+7x

The zeros of 8x^2+12=7x^2+7x are x=4,x=3

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8 x^{2} + 12 = 7 x^{2} + 7 x

x = 4, x = 3

Solution steps

8 x^{2} + 12 = 7 x^{2} + 7 x

Move

7 x

to the left side

8 x^{2} + 12 - 7 x = 7 x^{2}

Move

7 x^{2}

to the left side

x^{2} - 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

x = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

x = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 4, x = 3

2 x^{3} - 11 x^{2} + 5 x

t^{2} - 7 t = 0

\frac{1}{6} p = \frac{1}{5} p + \frac{2}{3}

4 (p - 6 p^{2} q) - 9 - 9 pq + 7 p (p + q) - 5 (3 + pq)

x^{2} - 18 x - 4 = 0

What are the solutions to the equation 8x^2+12=7x^2+7x ?
The solutions to the equation 8x^2+12=7x^2+7x are x=4,x=3
Find the zeros of 8x^2+12=7x^2+7x
The zeros of 8x^2+12=7x^2+7x are x=4,x=3