What are the solutions to the equation 2x^2-2x+1/2 =0 ?

The solutions to the equation 2x^2-2x+1/2 =0 are x= 1/2

Find the zeros of 2x^2-2x+1/2 =0

The zeros of 2x^2-2x+1/2 =0 are x= 1/2

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2 x^{2} - 2 x + \frac{1}{2} = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

2 x^{2} - 2 x + \frac{1}{2} = 0

Multiply both sides by

2

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

- 0.4 a + 3 = 7

5 x + 1 < - 4 or 6 x - 2 \geq 10

m^{2} - 4 m = 0

- 9 x^{2} + 12 x - 4 = 0

x^{5} y^{2} + x^{2} y^{5}

What are the solutions to the equation 2x^2-2x+1/2 =0 ?
The solutions to the equation 2x^2-2x+1/2 =0 are x= 1/2
Find the zeros of 2x^2-2x+1/2 =0
The zeros of 2x^2-2x+1/2 =0 are x= 1/2