What are the solutions to the equation 2x^2-18x=0 ?

The solutions to the equation 2x^2-18x=0 are x=9,x=0

Find the zeros of 2x^2-18x=0

The zeros of 2x^2-18x=0 are x=9,x=0

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2 x^{2} - 18 x = 0

x = 9, x = 0

Solution steps

2 x^{2} - 18 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 18)^{2} - 4 \cdot 2 \cdot 0 = 18

x_{1, 2} = \frac{- ( - 18 ) \pm 18}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 18}{2 \cdot 2}, x_{2} = \frac{- ( - 18 ) - 18}{2 \cdot 2}

x = \frac{- ( - 18 ) + 18}{2 \cdot 2} : 9

x = \frac{- ( - 18 ) - 18}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 9, x = 0

∣ x + 2 ∣ > 6

x^{2} + 67 = 18 x

- 4 < 2 x - 1 < 3

3 t^{2} - 24 t + 45 = 0

- \frac{18}{15}

What are the solutions to the equation 2x^2-18x=0 ?
The solutions to the equation 2x^2-18x=0 are x=9,x=0
Find the zeros of 2x^2-18x=0
The zeros of 2x^2-18x=0 are x=9,x=0