What is 1/(1+x)< 2/(3x-1) ?

The solution to 1/(1+x)< 2/(3x-1) is x<-1\lor 1/3 <x<3

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1/(1+x)< 2/(3x-1)

\frac{1}{1 + x} < \frac{2}{3 x - 1}

x < - 1 or \frac{1}{3} < x < 3

Interval Notation

(- \infty, - 1) \cup (\frac{1}{3}, 3)

Decimal Notation

x < - 1 or 0.33333 \dots < x < 3

Solution steps

\frac{1}{1 + x} < \frac{2}{3 x - 1}

Rewrite in standard form

\frac{x - 3}{( x + 1 ) ( 3 x - 1 )} < 0

Identify the intervals

x < - 1 or \frac{1}{3} < x < 3

(\frac{7}{x})^{2}

a^{9} + b^{9}

2 x + 1 = 2 x - 1

10 x^{2} - 9 x - 9

3^{2} + 2^{2} = x^{2}

What is 1/(1+x)< 2/(3x-1) ?
The solution to 1/(1+x)< 2/(3x-1) is x<-1\lor 1/3 <x<3