What are the solutions to the equation 3x^2-11x-2=0 ?

The solutions to the equation 3x^2-11x-2=0 are x=(11+sqrt(145))/6 ,x=(11-sqrt(145))/6

Find the zeros of 3x^2-11x-2=0

The zeros of 3x^2-11x-2=0 are x=(11+sqrt(145))/6 ,x=(11-sqrt(145))/6

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3 x^{2} - 11 x - 2 = 0

x = \frac{11 + 145}{6}, x = \frac{11 - 145}{6}

Decimal Notation

x = 3.84026 \dots, x = - 0.17359 \dots

Solution steps

3 x^{2} - 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 (- 2) = 145

x_{1, 2} = \frac{- ( - 11 ) \pm 145}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 145}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 145}{2 \cdot 3}

x = \frac{- ( - 11 ) + 145}{2 \cdot 3} : \frac{11 + 145}{6}

x = \frac{- ( - 11 ) - 145}{2 \cdot 3} : \frac{11 - 145}{6}

The solutions to the quadratic equation are:

x = \frac{11 + 145}{6}, x = \frac{11 - 145}{6}

e^{iπ} + 1

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(x + 3) (x - 1) = 32

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What are the solutions to the equation 3x^2-11x-2=0 ?
The solutions to the equation 3x^2-11x-2=0 are x=(11+sqrt(145))/6 ,x=(11-sqrt(145))/6
Find the zeros of 3x^2-11x-2=0
The zeros of 3x^2-11x-2=0 are x=(11+sqrt(145))/6 ,x=(11-sqrt(145))/6