What are the solutions to the equation 4x^2+3x-3=0 ?

The solutions to the equation 4x^2+3x-3=0 are x=(-3+sqrt(57))/8 ,x=(-3-sqrt(57))/8

Find the zeros of 4x^2+3x-3=0

The zeros of 4x^2+3x-3=0 are x=(-3+sqrt(57))/8 ,x=(-3-sqrt(57))/8

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4 x^{2} + 3 x - 3 = 0

x = \frac{- 3 + 57}{8}, x = \frac{- 3 - 57}{8}

Decimal Notation

x = 0.56872 \dots, x = - 1.31872 \dots

Solution steps

4 x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 3) = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 \cdot 4}, x_{2} = \frac{- 3 - 57}{2 \cdot 4}

x = \frac{- 3 + 57}{2 \cdot 4} : \frac{- 3 + 57}{8}

x = \frac{- 3 - 57}{2 \cdot 4} : \frac{- 3 - 57}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 57}{8}, x = \frac{- 3 - 57}{8}

60 0^{2}

x^{2} - 26 x + 169 = 0

x^{2} + 12 x + 24 = 0

- 3 < 5 - 2 x \leq 11

- 3 (y + 5) = 15

What are the solutions to the equation 4x^2+3x-3=0 ?
The solutions to the equation 4x^2+3x-3=0 are x=(-3+sqrt(57))/8 ,x=(-3-sqrt(57))/8
Find the zeros of 4x^2+3x-3=0
The zeros of 4x^2+3x-3=0 are x=(-3+sqrt(57))/8 ,x=(-3-sqrt(57))/8