What are the solutions to the equation x^2-26x+169=0 ?

The solutions to the equation x^2-26x+169=0 are x=13

Find the zeros of x^2-26x+169=0

The zeros of x^2-26x+169=0 are x=13

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x^{2} - 26 x + 169 = 0

x = 13

Solution steps

x^{2} - 26 x + 169 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot 169}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot 169 = 0

x_{1, 2} = \frac{- ( - 26 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 26 )}{2 \cdot 1}

\frac{- ( - 26 )}{2 \cdot 1} = 13

x = 13

The solution to the quadratic equation is:

x = 13

x^{2} + 12 x + 24 = 0

- 3 < 5 - 2 x \leq 11

- 3 (y + 5) = 15

- x^{2} + 5 x - 6 = 0

k M x - k x^{2}

What are the solutions to the equation x^2-26x+169=0 ?
The solutions to the equation x^2-26x+169=0 are x=13
Find the zeros of x^2-26x+169=0
The zeros of x^2-26x+169=0 are x=13