What are the solutions to the equation x^2+11x=-24 ?

The solutions to the equation x^2+11x=-24 are x=-3,x=-8

Find the zeros of x^2+11x=-24

The zeros of x^2+11x=-24 are x=-3,x=-8

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x^{2} + 11 x = - 24

x = - 3, x = - 8

Solution steps

x^{2} + 11 x = - 24

Move

24

to the left side

x^{2} + 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 \cdot 1}, x_{2} = \frac{- 11 - 5}{2 \cdot 1}

x = \frac{- 11 + 5}{2 \cdot 1} : - 3

x = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 3, x = - 8

3 x^{2} + 24 x = 0

- 6 m \leq - 36 and m + 24 \leq 20

- p + 50 = 3 p - 30

\frac{x - 6}{5} = \frac{x + 1}{6}

3 x^{4} - 2 x^{3} + 11 x^{2} - 8 x - 4

What are the solutions to the equation x^2+11x=-24 ?
The solutions to the equation x^2+11x=-24 are x=-3,x=-8
Find the zeros of x^2+11x=-24
The zeros of x^2+11x=-24 are x=-3,x=-8