What are the solutions to the equation 5x^2+1=2x ?

The solutions to the equation 5x^2+1=2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5

Find the zeros of 5x^2+1=2x

The zeros of 5x^2+1=2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5

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5 x^{2} + 1 = 2 x

x = \frac{1}{5} + i \frac{2}{5}, x = \frac{1}{5} - i \frac{2}{5}

Solution steps

5 x^{2} + 1 = 2 x

Move

2 x

to the left side

5 x^{2} + 1 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

(- 2)^{2} - 4 \cdot 5 \cdot 1 : 4 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 5}

x = \frac{- ( - 2 ) + 4 i}{2 \cdot 5} : \frac{1}{5} + i \frac{2}{5}

x = \frac{- ( - 2 ) - 4 i}{2 \cdot 5} : \frac{1}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5} + i \frac{2}{5}, x = \frac{1}{5} - i \frac{2}{5}

6 x - x^{2} - x^{3}

(x - 2)^{2} > (x + 2) (x - 2) + 8

81 + 20 - 45

∣ b ∣ = 0^{2} + 0^{2} + 3^{2}

2 x^{2} + 2 x - 7 = 0

What are the solutions to the equation 5x^2+1=2x ?
The solutions to the equation 5x^2+1=2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5
Find the zeros of 5x^2+1=2x
The zeros of 5x^2+1=2x are x= 1/5+i 2/5 ,x= 1/5-i 2/5