What is factor 1/25+25/36 b^4-(b^2)/3 ?

The solution to factor 1/25+25/36 b^4-(b^2)/3 is 1/25+(25b^4}{36}-\frac{b^2)/3

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factor 1/25+25/36 b^4-(b^2)/3

factor

\frac{1}{25} + \frac{25}{36} b^{4} - \frac{b ^{2}}{3}

\frac{1}{25} + \frac{25 b ^{4}}{36} - \frac{b ^{2}}{3}

Solution steps

\frac{1}{25} + \frac{25}{36} b^{4} - \frac{b ^{2}}{3}

Multiply

\frac{25}{36} b^{4} : \frac{25 b ^{4}}{36}

= \frac{1}{25} + \frac{25 b ^{4}}{36} - \frac{b ^{2}}{3}

3 y^{2} + 5 y - 10 = 0

\frac{1 2 ^{2}}{4 ^{2}}

\frac{2}{7} x + \frac{2}{5} = \frac{19}{35}

\frac{5}{3} \cdot (- \frac{6}{7})

\frac{2 - 3 i}{1 - 2 i}

What is factor 1/25+25/36 b^4-(b^2)/3 ?
The solution to factor 1/25+25/36 b^4-(b^2)/3 is 1/25+(25b^4}{36}-\frac{b^2)/3