What are the solutions to the equation -6x^2-3x+10=-5x^2 ?

The solutions to the equation -6x^2-3x+10=-5x^2 are x=-5,x=2

Find the zeros of -6x^2-3x+10=-5x^2

The zeros of -6x^2-3x+10=-5x^2 are x=-5,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 6 x^{2} - 3 x + 10 = - 5 x^{2}

x = - 5, x = 2

Solution steps

- 6 x^{2} - 3 x + 10 = - 5 x^{2}

Move

5 x^{2}

to the left side

- x^{2} - 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 10 = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 7}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 7}{2 ( - 1 )} : - 5

x = \frac{- ( - 3 ) - 7}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 5, x = 2

(5 k - 4)^{2} = 36

9 x^{2} - 7 x - 5 = 0

\frac{( 300 P + 6000 )}{300 P} = 35%

\frac{- 6 x ^{2} - 2 e ^{y}}{3 x ^{2} y + e ^{y}}

3 x^{2} + 17 x - 28

What are the solutions to the equation -6x^2-3x+10=-5x^2 ?
The solutions to the equation -6x^2-3x+10=-5x^2 are x=-5,x=2
Find the zeros of -6x^2-3x+10=-5x^2
The zeros of -6x^2-3x+10=-5x^2 are x=-5,x=2