What is (x-2)(x+1)(2x+3)<= 0 ?

The solution to (x-2)(x+1)(2x+3)<= 0 is x<=-3/2 \lor-1<= x<= 2

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(x-2)(x+1)(2x+3)<= 0

(x - 2) (x + 1) (2 x + 3) \leq 0

x \leq - \frac{3}{2} or - 1 \leq x \leq 2

Interval Notation

(- \infty, - \frac{3}{2}] \cup [- 1, 2]

Decimal Notation

x \leq - 1.5 or - 1 \leq x \leq 2

Solution steps

(x - 2) (x + 1) (2 x + 3) \leq 0

Identify the intervals

x \leq - \frac{3}{2} or - 1 \leq x \leq 2

\frac{5}{3 + 4 3}

∣ x + 1 ∣ + ∣ x - 1 ∣ = 2

(2 x + 7) (2 x - 7) = 0

\frac{( 1 + i ) ( 1 - i ) ^{4}}{( 1 + 2 i ) ^{3}}

∣ x ∣ \geq 9

What is (x-2)(x+1)(2x+3)<= 0 ?
The solution to (x-2)(x+1)(2x+3)<= 0 is x<=-3/2 \lor-1<= x<= 2