What are the solutions to the equation -4x^2+6x+3=0 ?

The solutions to the equation -4x^2+6x+3=0 are x=-(-3+sqrt(21))/4 ,x=(3+sqrt(21))/4

Find the zeros of -4x^2+6x+3=0

The zeros of -4x^2+6x+3=0 are x=-(-3+sqrt(21))/4 ,x=(3+sqrt(21))/4

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- 4 x^{2} + 6 x + 3 = 0

x = - \frac{- 3 + 21}{4}, x = \frac{3 + 21}{4}

Decimal Notation

x = - 0.39564 \dots, x = 1.89564 \dots

Solution steps

- 4 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

6^{2} - 4 (- 4) \cdot 3 = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 ( - 4 )}, x_{2} = \frac{- 6 - 2 21}{2 ( - 4 )}

x = \frac{- 6 + 2 21}{2 ( - 4 )} : - \frac{- 3 + 21}{4}

x = \frac{- 6 - 2 21}{2 ( - 4 )} : \frac{3 + 21}{4}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 21}{4}, x = \frac{3 + 21}{4}

28 - 7 x^{2} = 0

3 p^{2} + 14 p - 24

1 x^{2} + 2 x + 3 = 0

2 x - \frac{1}{2} \geq 7 x + \frac{7}{6}

\frac{4}{9} - \frac{5}{8} (\frac{1}{3})^{2}

What are the solutions to the equation -4x^2+6x+3=0 ?
The solutions to the equation -4x^2+6x+3=0 are x=-(-3+sqrt(21))/4 ,x=(3+sqrt(21))/4
Find the zeros of -4x^2+6x+3=0
The zeros of -4x^2+6x+3=0 are x=-(-3+sqrt(21))/4 ,x=(3+sqrt(21))/4