What is 1/(a^2+2a+1)+1/(a+1) ?

The solution to 1/(a^2+2a+1)+1/(a+1) is (a+2)/((a+1)^2)

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simplify 1/(a^2+2a+1)+1/(a+1)

simplify

\frac{1}{a ^{2} + 2 a + 1} + \frac{1}{a + 1}

\frac{a + 2}{( a + 1 ) ^{2}}

Solution steps

\frac{1}{a ^{2} + 2 a + 1} + \frac{1}{a + 1}

Least Common Multiplier of

a^{2} + 2 a + 1, a + 1 : (a + 1)^{2}

Adjust Fractions based on the LCM

= \frac{1}{( a + 1 ) ^{2}} + \frac{a + 1}{( a + 1 ) ^{2}}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{1 + a + 1}{( a + 1 ) ^{2}}

Simplify

1 + a + 1 : a + 2

= \frac{a + 2}{( a + 1 ) ^{2}}

(x + 1) (x - 1) = 2 (x + 5) + 4

3 x + 5 > - 16

- 4 k^{2} + 16 k > 0

64 n^{4} - 192 n^{3} + 27 n - 81

- \frac{1}{4} x + \frac{3}{8} \leq 1

What is 1/(a^2+2a+1)+1/(a+1) ?
The solution to 1/(a^2+2a+1)+1/(a+1) is (a+2)/((a+1)^2)