What are the solutions to the equation (t-3)^2=6 ?

The solutions to the equation (t-3)^2=6 are t=sqrt(6)+3,t=-sqrt(6)+3

Find the zeros of (t-3)^2=6

The zeros of (t-3)^2=6 are t=sqrt(6)+3,t=-sqrt(6)+3

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(t - 3)^{2} = 6

t = 6 + 3, t = - 6 + 3

Decimal Notation

t = 5.44948 \dots, t = 0.55051 \dots

Solution steps

(t - 3)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - 3 = 6 : t = 6 + 3

Solve

t - 3 = - 6 : t = - 6 + 3

The solutions to the quadratic equation are:

t = 6 + 3, t = - 6 + 3

x^{2} - 14 x - 95 = 0

12 x^{2} + 11 x + 2 = 0

m + 4 < 0

k^{2} = 14

\frac{1}{P ( M - P )} d P

What are the solutions to the equation (t-3)^2=6 ?
The solutions to the equation (t-3)^2=6 are t=sqrt(6)+3,t=-sqrt(6)+3
Find the zeros of (t-3)^2=6
The zeros of (t-3)^2=6 are t=sqrt(6)+3,t=-sqrt(6)+3