What are the solutions to the equation 49x^2+14x+1=0 ?

The solutions to the equation 49x^2+14x+1=0 are x=-1/7

Find the zeros of 49x^2+14x+1=0

The zeros of 49x^2+14x+1=0 are x=-1/7

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49 x^{2} + 14 x + 1 = 0

x = - \frac{1}{7}

Solution steps

49 x^{2} + 14 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 49 \cdot 1}{2 \cdot 49}

1 4^{2} - 4 \cdot 49 \cdot 1 = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 49}

x = \frac{- 14}{2 \cdot 49}

\frac{- 14}{2 \cdot 49} = - \frac{1}{7}

x = - \frac{1}{7}

The solution to the quadratic equation is:

x = - \frac{1}{7}

4 x^{2} - 6 x + 9 = 0

5 (x - 4)^{2} = 5

\frac{x ^{2} - 1}{5} = 7

- \frac{3}{5} - 1

(\frac{1}{3})^{7}

What are the solutions to the equation 49x^2+14x+1=0 ?
The solutions to the equation 49x^2+14x+1=0 are x=-1/7
Find the zeros of 49x^2+14x+1=0
The zeros of 49x^2+14x+1=0 are x=-1/7