What are the solutions to the equation x^2-x+1=0 ?

The solutions to the equation x^2-x+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

Find the zeros of x^2-x+1=0

The zeros of x^2-x+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

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x^{2} - x + 1 = 0

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 1 : 3 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 1 ) - 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

1 + x^{2} + 2 x

0.9 = (40 \cdot (x)) \cdot \frac{1}{0.000000823}

78 \geq 312

3 252 k^{5}

(a + b) (a + b)

What are the solutions to the equation x^2-x+1=0 ?
The solutions to the equation x^2-x+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2
Find the zeros of x^2-x+1=0
The zeros of x^2-x+1=0 are x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2