What is factor 64t^6-1 ?

The solution to factor 64t^6-1 is (2t+1)(2t-1)(4t^2+2t+1)(4t^2-2t+1)

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factor 64t^6-1

factor

64 t^{6} - 1

(2 t + 1) (2 t - 1) (4 t^{2} + 2 t + 1) (4 t^{2} - 2 t + 1)

Solution steps

64 t^{6} - 1

Apply exponent rules

= (4 t^{2})^{3} - 1^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(4 t^{2})^{3} - 1^{3} = (4 t^{2} - 1) (4^{2} t^{4} + 4 t^{2} + 1)

= (4 t^{2} - 1) (4^{2} t^{4} + 4 t^{2} + 1)

Factor

4 t^{2} - 1 : (2 t + 1) (2 t - 1)

= (2 t + 1) (2 t - 1) (4^{2} t^{4} + 4 t^{2} + 1)

Factor

4^{2} t^{4} + 4 t^{2} + 1 : (4 t^{2} + 1 + 2 t) (4 t^{2} + 1 - 2 t)

= (2 t + 1) (2 t - 1) (4 t^{2} + 1 + 2 t) (4 t^{2} + 1 - 2 t)

= (2 t + 1) (2 t - 1) (4 t^{2} + 2 t + 1) (4 t^{2} - 2 t + 1)

\frac{1}{3} + \frac{1}{6}

1. 4^{2}

2 k (- 3 k + 4) + 6 (k^{2} + 10) = k (4 k + 8) - 2 k (2 k + 5)

(1 - i) (- 2 + i)

- 14.5 = 0.5 x - 14.5

What is factor 64t^6-1 ?
The solution to factor 64t^6-1 is (2t+1)(2t-1)(4t^2+2t+1)(4t^2-2t+1)