What are the solutions to the equation 3x(x+1)+4=6-2x ?

The solutions to the equation 3x(x+1)+4=6-2x are x= 1/3 ,x=-2

Find the zeros of 3x(x+1)+4=6-2x

The zeros of 3x(x+1)+4=6-2x are x= 1/3 ,x=-2

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3 x (x + 1) + 4 = 6 - 2 x

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

3 x (x + 1) + 4 = 6 - 2 x

Expand

3 x (x + 1) + 4 : 3 x^{2} + 3 x + 4

3 x^{2} + 3 x + 4 = 6 - 2 x

Move

2 x

to the left side

3 x^{2} + 5 x + 4 = 6

Move

6

to the left side

3 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 2) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 3}, x_{2} = \frac{- 5 - 7}{2 \cdot 3}

x = \frac{- 5 + 7}{2 \cdot 3} : \frac{1}{3}

x = \frac{- 5 - 7}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

c + 7 \leq 3

6 a^{2} - 7 a + 2

14 x^{2} - 3 x - 2

12 x^{2} - 15 x - 6 = 0

3 y^{2} - y = 2

What are the solutions to the equation 3x(x+1)+4=6-2x ?
The solutions to the equation 3x(x+1)+4=6-2x are x= 1/3 ,x=-2
Find the zeros of 3x(x+1)+4=6-2x
The zeros of 3x(x+1)+4=6-2x are x= 1/3 ,x=-2