What are the solutions to the equation y^2+8y+7=0 ?

The solutions to the equation y^2+8y+7=0 are y=-1,y=-7

Find the zeros of y^2+8y+7=0

The zeros of y^2+8y+7=0 are y=-1,y=-7

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y^{2} + 8 y + 7 = 0

y = - 1, y = - 7

Solution steps

y^{2} + 8 y + 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

y_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 6}{2 \cdot 1}, y_{2} = \frac{- 8 - 6}{2 \cdot 1}

y = \frac{- 8 + 6}{2 \cdot 1} : - 1

y = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = - 1, y = - 7

- 16 = \frac{2}{3} x

\frac{- 11 - 3 i}{1 - 2 i}

\frac{( 1 + 4 i ) ( 2 - 3 i )}{( 1 - 2 i )}

(x + 12)^{2} = 25

15 x = 0

What are the solutions to the equation y^2+8y+7=0 ?
The solutions to the equation y^2+8y+7=0 are y=-1,y=-7
Find the zeros of y^2+8y+7=0
The zeros of y^2+8y+7=0 are y=-1,y=-7