What is ((1+4i)(2-3i))/((1-2i)) ?

The solution to ((1+4i)(2-3i))/((1-2i)) is 4/5+33/5 i

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simplify ((1+4i)(2-3i))/((1-2i))

simplify

\frac{( 1 + 4 i ) ( 2 - 3 i )}{( 1 - 2 i )}

\frac{4}{5} + \frac{33}{5} i

Solution steps

\frac{( 1 + 4 i ) ( 2 - 3 i )}{1 - 2 i}

Multiply by the conjugate

\frac{1 + 2 i}{1 + 2 i}

= \frac{( 1 + 4 i ) ( 2 - 3 i ) ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )}

Simplify

\frac{( 1 + 4 i ) ( 2 - 3 i ) ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )} : \frac{4 + 33 i}{5}

= \frac{4 + 33 i}{5}

Rewrite in standard complex form:

\frac{4}{5} + \frac{33}{5} i

= \frac{4}{5} + \frac{33}{5} i

(x + 12)^{2} = 25

15 x = 0

9 x^{2} - 2 x - 1 = 0

- 75 + 63

\frac{( - 8 x ^{3} y ^{2} ) ^{2} \cdot 2 x ^{2} y ^{6}}{32 x ^{8} y ^{3}}

What is ((1+4i)(2-3i))/((1-2i)) ?
The solution to ((1+4i)(2-3i))/((1-2i)) is 4/5+33/5 i