What are the solutions to the equation 5x^2+7=16x+4 ?

The solutions to the equation 5x^2+7=16x+4 are x=3,x= 1/5

Find the zeros of 5x^2+7=16x+4

The zeros of 5x^2+7=16x+4 are x=3,x= 1/5

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5 x^{2} + 7 = 16 x + 4

x = 3, x = \frac{1}{5}

Decimal Notation

x = 3, x = 0.2

Solution steps

5 x^{2} + 7 = 16 x + 4

Move

4

to the left side

5 x^{2} + 3 = 16 x

Move

16 x

to the left side

5 x^{2} + 3 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 16 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

(- 16)^{2} - 4 \cdot 5 \cdot 3 = 14

x_{1, 2} = \frac{- ( - 16 ) \pm 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 14}{2 \cdot 5}, x_{2} = \frac{- ( - 16 ) - 14}{2 \cdot 5}

x = \frac{- ( - 16 ) + 14}{2 \cdot 5} : 3

x = \frac{- ( - 16 ) - 14}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 3, x = \frac{1}{5}

32 + 16 + 8

45 = - 2 (x + 7)^{2}

5 x^{2} - 22 x - 15

∣ x + 1 ∣ = x^{2} - 5

What are the solutions to the equation 5x^2+7=16x+4 ?
The solutions to the equation 5x^2+7=16x+4 are x=3,x= 1/5
Find the zeros of 5x^2+7=16x+4
The zeros of 5x^2+7=16x+4 are x=3,x= 1/5