What is the solution for (dy)/(dx)=-sin^2(x+y) ?

The solution for (dy)/(dx)=-sin^2(x+y) is y=arctan(x+c_{1})+pin-x

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(dy)/(dx)=-sin^2(x+y)

\frac{d y}{d x} = - sin^{2} (x + y)

y = arctan (x + c_{1}) + πn - x

Solution steps

\frac{d y}{d x} = - sin^{2} (x + y)

Solve using substitution:

y = arctan (x + c_{1}) + πn - x

y = arctan (x + c_{1}) + πn - x

\int_{- 1}^{1} x + 2 d x

x \to 2 lim (\frac{2 - x}{2 x ^{2} - 4})

y = 9 x^{2}, y = x^{2} + 6

\int cos^{7} (y) d y

What is the solution for (dy)/(dx)=-sin^2(x+y) ?
The solution for (dy)/(dx)=-sin^2(x+y) is y=arctan(x+c_{1})+pin-x