What is the solution for 8x^2y+y^'=10x^2 ?

The solution for 8x^2y+y^'=10x^2 is y=(e^{(-8x^3+c_{1})/3})/(4)+5/4

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8x^2y+y^'=10x^2

8 x^{2} y + y^{^{'}} = 10 x^{2}

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{4} + \frac{5}{4}

Solution steps

8 x^{2} y + y^{'} (x) = 10 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{4} + \frac{5}{4}

y = \frac{e ^{\frac{- 8 x ^{3} + c _{1}}{3}}}{4} + \frac{5}{4}

4 x^{3} - 33 x^{2} + 84 x - 60

\frac{d}{d x} (2 x 16 - x^{2})

\frac{\partial}{\partial x} (2 x^{2} + y^{3})

f (x) = \frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}

\frac{500}{12 + 5 e ^{- 0.5 t}}

What is the solution for 8x^2y+y^'=10x^2 ?
The solution for 8x^2y+y^'=10x^2 is y=(e^{(-8x^3+c_{1})/3})/(4)+5/4