What is the slope of sqrt(sin(cos^2(x))),\at x=pi ?

The slope of sqrt(sin(cos^2(x))),\at x=pi is 0

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slope of sqrt(sin(cos^2(x))),\at x=pi

slope

sin (cos^{2} (x)), at x = π

0

Solution steps

y = sin (cos^{2} (x))

In order to find the slope of the function, take the derivative of

sin (cos^{2} (x))

\frac{d}{d x} (sin (cos^{2} (x))) = - \frac{cos ( cos ^{2} ( x ) ) sin ( 2 x )}{2 sin ( cos ^{2} ( x ) )}

- \frac{cos ( cos ^{2} ( x ) ) sin ( 2 x )}{2 sin ( cos ^{2} ( x ) )}

Find the value of

- \frac{cos ( cos ^{2} ( x ) ) sin ( 2 x )}{2 sin ( cos ^{2} ( x ) )}

for

x = π : 0

0

\frac{6 + x}{1 - 6 x}

\frac{6}{s ^{2}}

\frac{d x}{d t} = 3 x^{2} + 2 x

\frac{d}{d x} (\frac{arcsin ( x )}{1 - x ^{2}})

What is the slope of sqrt(sin(cos^2(x))),\at x=pi ?
The slope of sqrt(sin(cos^2(x))),\at x=pi is 0