What is the tangent of 3x^2,\at x=-1 ?

The tangent of 3x^2,\at x=-1 is y=-6x-3

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tangent of 3x^2,\at x=-1

tangent of

3 x^{2}, at x = - 1

y = - 6 x - 3

Solution steps

Find the tangent point:

(- 1, 3)

Find the slope of

y = 3 x^{2} : \frac{d y}{d x} = 6 x

Compute the slope of

y = 3 x^{2}

x = - 1 : m = - 6

Find the line with slope m=

- 6

and passing through

(- 1, 3) : y = - 6 x - 3

y = - 6 x - 3

y = ln (x - 3)

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