What is (\partial}{\partial s}(\frac{2r+s)/t) ?

The answer to (\partial}{\partial s}(\frac{2r+s)/t) is 1/t

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(\partial}{\partial s}(\frac{2r+s)/t)

\frac{\partial}{\partial s} (\frac{2 r + s}{t})

\frac{1}{t}

Solution steps

\frac{\partial}{\partial s} (\frac{2 r + s}{t})

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t} \frac{\partial}{\partial s} (2 r + s)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t} (\frac{\partial}{\partial s} (2 r) + \frac{\partial}{\partial s} (s))

\frac{\partial}{\partial s} (2 r) = 0

\frac{\partial}{\partial s} (s) = 1

= \frac{1}{t} (0 + 1)

Simplify

= \frac{1}{t}

y^{^{'}} + \frac{2}{x} y = - 2 x y^{2}

3 x^{2} + 7 x - 4

1 - 289 x^{2} arccos (17 x)

h \to 0 lim \frac{( ( \frac{1}{1 - ( x + h )} ) - ( \frac{1}{1 - x} ) )}{h}

\frac{d}{d x} (\frac{1}{( x + y )})

What is (\partial}{\partial s}(\frac{2r+s)/t) ?
The answer to (\partial}{\partial s}(\frac{2r+s)/t) is 1/t