What is the solution for (dy)/(dt)= 1/(y-2) ?

The solution for (dy)/(dt)= 1/(y-2) is y=(4+sqrt(16-4(-c_{1)-2t)})/2 ,y=(4-sqrt(16-4(-c_{1)-2t)})/2

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(dy)/(dt)= 1/(y-2)

\frac{d y}{d t} = \frac{1}{y - 2}

y = \frac{4 + 16 - 4 ( - c _{1} - 2 t )}{2}, y = \frac{4 - 16 - 4 ( - c _{1} - 2 t )}{2}

Solution steps

\frac{d y}{d t} = \frac{1}{y - 2}

Solve separable ODE:

y = \frac{4 + 16 - 4 ( - c _{1} - 2 t )}{2}, y = \frac{4 - 16 - 4 ( - c _{1} - 2 t )}{2}

y = \frac{4 + 16 - 4 ( - c _{1} - 2 t )}{2}, y = \frac{4 - 16 - 4 ( - c _{1} - 2 t )}{2}

\int_{0}^{1} 4 x y e^{- (2 x + y)} d y

n = 0 \sum \infty (- \frac{5}{6})^{n}

\int cos^{2} (θ) + sin^{2} (θ) d θ

\frac{\partial ^{2}}{\partial x \partial y} (\frac{x y}{x - y})

x \to + 0 lim (x^{4} cos (\frac{π}{x}))

What is the solution for (dy)/(dt)= 1/(y-2) ?
The solution for (dy)/(dt)= 1/(y-2) is y=(4+sqrt(16-4(-c_{1)-2t)})/2 ,y=(4-sqrt(16-4(-c_{1)-2t)})/2