What is (\partial)/(\partial x)(e^{2x}+e^{-2x}) ?

The answer to (\partial)/(\partial x)(e^{2x}+e^{-2x}) is e^{2x}*2-2e^{-2x}

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(\partial)/(\partial x)(e^{2x}+e^{-2x})

\frac{\partial}{\partial x} (e^{2 x} + e^{- 2 x})

e^{2 x} \cdot 2 - 2 e^{- 2 x}

Solution steps

\frac{\partial}{\partial x} (e^{2 x} + e^{- 2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{2 x}) + \frac{\partial}{\partial x} (e^{- 2 x})

\frac{\partial}{\partial x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{\partial}{\partial x} (e^{- 2 x}) = - 2 e^{- 2 x}

= e^{2 x} \cdot 2 - 2 e^{- 2 x}

x \to 0 lim (\frac{3 ^{x} - 1}{x})

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What is (\partial)/(\partial x)(e^{2x}+e^{-2x}) ?
The answer to (\partial)/(\partial x)(e^{2x}+e^{-2x}) is e^{2x}*2-2e^{-2x}