What is the sum from n=0 to infinity of 1^{ln(n)} ?

The sum from n=0 to infinity of 1^{ln(n)} is diverges

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sum from n=0 to infinity of 1^{ln(n)}

n = 0 \sum \infty 1^{l n (n)}

diverges

Solution steps

n = 1 \sum \infty 1^{l n (n)}

Simplify

= n = 1 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

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What is the sum from n=0 to infinity of 1^{ln(n)} ?
The sum from n=0 to infinity of 1^{ln(n)} is diverges