What is the derivative of \sqrt[7]{x}^{ln(x}) ?

The derivative of \sqrt[7]{x}^{ln(x}) is (2e^{(ln^2(x))/7}ln(x))/(7x)

What is the first derivative of \sqrt[7]{x}^{ln(x}) ?

The first derivative of \sqrt[7]{x}^{ln(x}) is (2e^{(ln^2(x))/7}ln(x))/(7x)

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\frac{2 e ^{\frac{l n ^{2} ( x )}{7}} ln ( x )}{7 x}

Solution steps

Apply exponent rule:

a^{b} = e^{b l n (a)}

Apply the chain rule:

Simplify

= \frac{2 e ^{\frac{l n ^{2} ( x )}{7}} ln ( x )}{7 x}

\int \frac{7}{x ^{8}} d x

\frac{1}{4 - x}

x \to 0 + lim (tan^{x} (x))

\frac{d y}{d x} - \frac{2 y}{x} = - x^{2} y^{2}

\frac{d}{d x} (x e^{3 y})

What is the derivative of \sqrt[7]{x}^{ln(x}) ?
The derivative of \sqrt[7]{x}^{ln(x}) is (2e^{(ln^2(x))/7}ln(x))/(7x)
What is the first derivative of \sqrt[7]{x}^{ln(x}) ?
The first derivative of \sqrt[7]{x}^{ln(x}) is (2e^{(ln^2(x))/7}ln(x))/(7x)