What is the solution for (dy}{dx}-\frac{2y)/x =-x^2y^2 ?

The solution for (dy}{dx}-\frac{2y)/x =-x^2y^2 is y=(5x^2)/(x^5+c_{1)}

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(dy}{dx}-\frac{2y)/x =-x^2y^2

\frac{d y}{d x} - \frac{2 y}{x} = - x^{2} y^{2}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

Solution steps

\frac{d y}{d x} - \frac{2 y}{x} = - x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

\frac{d}{d x} (x e^{3 y})

\frac{d y}{d x} = y^{2} (4 x + 1)

\frac{1}{t} y^{^{'}} = \frac{y}{t ^{2}} - \frac{1}{y}

f (x) = \frac{1}{5 + 3 x}, (1, \frac{1}{8})

- \frac{2}{s + \frac{1}{3}}

What is the solution for (dy}{dx}-\frac{2y)/x =-x^2y^2 ?
The solution for (dy}{dx}-\frac{2y)/x =-x^2y^2 is y=(5x^2)/(x^5+c_{1)}