What is the limit as x approaches 0+of tan^x(x) ?

The limit as x approaches 0+of tan^x(x) is 1

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limit as x approaches 0+of tan^x(x)

x \to 0 + lim (tan^{x} (x))

1

Solution steps

x \to 0 + lim (tan^{x} (x))

Apply exponent rules

= x \to 0 + lim (e^{x l n (t a n (x))})

Apply the Limit Chain Rule:

1

= 1

\frac{d y}{d x} - \frac{2 y}{x} = - x^{2} y^{2}

\frac{d}{d x} (x e^{3 y})

\frac{d y}{d x} = y^{2} (4 x + 1)

\frac{1}{t} y^{^{'}} = \frac{y}{t ^{2}} - \frac{1}{y}

f (x) = \frac{1}{5 + 3 x}, (1, \frac{1}{8})

What is the limit as x approaches 0+of tan^x(x) ?
The limit as x approaches 0+of tan^x(x) is 1