What is the tangent of f(x)= 1/(5+3x),(1, 1/8) ?

The tangent of f(x)= 1/(5+3x),(1, 1/8) is y=-3/64 x+11/64

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tangent of f(x)= 1/(5+3x),(1, 1/8)

tangent of

f (x) = \frac{1}{5 + 3 x}, (1, \frac{1}{8})

y = - \frac{3}{64} x + \frac{11}{64}

Solution steps

Find the slope of

f (x) = \frac{1}{5 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 5 + 3 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{5 + 3 x}

(1, \frac{1}{8}) : m = - \frac{3}{64}

Find the line with slope m=

- \frac{3}{64}

and passing through

(1, \frac{1}{8}) : y = - \frac{3}{64} x + \frac{11}{64}

y = - \frac{3}{64} x + \frac{11}{64}

- \frac{2}{s + \frac{1}{3}}

\frac{\partial}{\partial x} (sin (π (2 x - 3 y)))

x \to 0 + lim ((2 x^{2} + x)^{x})

x \to 3 lim (\frac{( x + 2 )}{x + 3})

e^{2 x}, x = 0

What is the tangent of f(x)= 1/(5+3x),(1, 1/8) ?
The tangent of f(x)= 1/(5+3x),(1, 1/8) is y=-3/64 x+11/64