What is the derivative of (2x^4-x+1(-x^5+7)) ?

The derivative of (2x^4-x+1(-x^5+7)) is -18x^8+6x^5-5x^4+56x^3-7

What is the first derivative of (2x^4-x+1(-x^5+7)) ?

The first derivative of (2x^4-x+1(-x^5+7)) is -18x^8+6x^5-5x^4+56x^3-7

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\frac{d}{d x} ((2 x^{4} - x + 1) (- x^{5} + 7))

- 18 x^{8} + 6 x^{5} - 5 x^{4} + 56 x^{3} - 7

Solution steps

\frac{d}{d x} ((2 x^{4} - x + 1) (- x^{5} + 7))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x^{4} - x + 1, g = - x^{5} + 7

= \frac{d}{d x} (2 x^{4} - x + 1) (- x^{5} + 7) + \frac{d}{d x} (- x^{5} + 7) (2 x^{4} - x + 1)

\frac{d}{d x} (2 x^{4} - x + 1) = 8 x^{3} - 1

\frac{d}{d x} (- x^{5} + 7) = - 5 x^{4}

= (8 x^{3} - 1) (- x^{5} + 7) + (- 5 x^{4}) (2 x^{4} - x + 1)

Simplify

(8 x^{3} - 1) (- x^{5} + 7) + (- 5 x^{4}) (2 x^{4} - x + 1) : - 18 x^{8} + 6 x^{5} - 5 x^{4} + 56 x^{3} - 7

= - 18 x^{8} + 6 x^{5} - 5 x^{4} + 56 x^{3} - 7

\int_{0}^{x} t^{2} d t

h (x) = (- 2 x - 3)^{5} (3 x + 1)^{3}

f (x) = x^{4}, at x = 2

\int (\frac{9 + x}{x})^{2} d x

\int - csc (2 x) cot (2 x) d x

What is the derivative of (2x^4-x+1(-x^5+7)) ?
The derivative of (2x^4-x+1(-x^5+7)) is -18x^8+6x^5-5x^4+56x^3-7
What is the first derivative of (2x^4-x+1(-x^5+7)) ?
The first derivative of (2x^4-x+1(-x^5+7)) is -18x^8+6x^5-5x^4+56x^3-7