What is the integral of 1/x sin(x) ?

The integral of 1/x sin(x) is \Si(x)+C

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integral of 1/x sin(x)

\int \frac{1}{x} sin (x) d x

Si (x) + C

Solution steps

\int \frac{1}{x} sin (x) d x

Simplify

\frac{1}{x} sin (x) : \frac{sin ( x )}{x}

= \int \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= Si (x)

Add a constant to the solution

= Si (x) + C

\int_{1}^{\infty} \frac{1}{x ^{1}} d x

f (x) = (3 x^{3} - 2) (x + 1)

\frac{d}{d x} (8 x e^{x} - 8 e^{x})

y = 4 x - 3 x^{2}, (2, - 4)

n = 0 \sum \infty \frac{n ^{4}}{4 ^{n}}