What is the derivative of f(x)=x^3-5 ?

The derivative of f(x)=x^3-5 is 3x^2

What is the first derivative of f(x)=x^3-5 ?

The first derivative of f(x)=x^3-5 is 3x^2

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derivative of

f (x) = x^{3} - 5

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

\frac{d}{d x} (\frac{1}{x ^{4} + x ^{2} + 1})

\frac{d y}{d x} = \frac{( 2 x ^{4} + 2 y )}{- 2 x - 3 y}

- 2 sin (2 t)

\int \frac{4}{3 + 4 x} d x

\int_{1}^{49} \frac{1}{2 x} d x

What is the derivative of f(x)=x^3-5 ?
The derivative of f(x)=x^3-5 is 3x^2
What is the first derivative of f(x)=x^3-5 ?
The first derivative of f(x)=x^3-5 is 3x^2