What is the derivative of-2sin(2t) ?

The derivative of-2sin(2t) is -4cos(2t)

What is the first derivative of-2sin(2t) ?

The first derivative of-2sin(2t) is -4cos(2t)

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derivative of

- 2 sin (2 t)

- 4 cos (2 t)

Solution steps

\frac{d}{d t} (- 2 sin (2 t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d t} (sin (2 t))

Apply the chain rule:

cos (2 t) \frac{d}{d t} (2 t)

= cos (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= - 2 cos (2 t) \cdot 2

Simplify

= - 4 cos (2 t)

\int \frac{4}{3 + 4 x} d x

\int_{1}^{49} \frac{1}{2 x} d x

\frac{d}{d x} (\frac{x ^{2}}{3})

t \cdot e^{- 5 t}

f (x) = 5 x + 4

What is the derivative of-2sin(2t) ?
The derivative of-2sin(2t) is -4cos(2t)
What is the first derivative of-2sin(2t) ?
The first derivative of-2sin(2t) is -4cos(2t)