What is the tangent of f(x)=4x^2,\at x=9 ?

The tangent of f(x)=4x^2,\at x=9 is y=72x-324

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=4x^2,\at x=9

tangent of

f (x) = 4 x^{2}, at x = 9

y = 72 x - 324

Solution steps

Find the tangent point:

(9, 324)

Find the slope of

f (x) = 4 x^{2} : \frac{df ( x )}{d x} = 8 x

Compute the slope of

f (x) = 4 x^{2}

x = 9 : m = 72

Find the line with slope m=

72

and passing through

(9, 324) : y = 72 x - 324

y = 72 x - 324

4 x^{- 1}

- 4 x^{2} + 6.25 x + 8, 2.5 x + 7

\int (sec (x) - 2 x tan (x) - 2 x) d x

\frac{d}{d x} (- 2 ln (\frac{3}{2} x))

7 y^{^{'}} + 5 y = 2 e^{3 x}

What is the tangent of f(x)=4x^2,\at x=9 ?
The tangent of f(x)=4x^2,\at x=9 is y=72x-324