What is the limit as x approaches 0 of (8sin(3x))/(1-cos(3x)) ?

The limit as x approaches 0 of (8sin(3x))/(1-cos(3x)) is diverges

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limit as x approaches 0 of (8sin(3x))/(1-cos(3x))

x \to 0 lim (\frac{8 sin ( 3 x )}{1 - cos ( 3 x )})

diverges

Solution steps

x \to 0 lim (\frac{8 sin ( 3 x )}{1 - cos ( 3 x )})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{8 sin ( 3 x )}{1 - cos ( 3 x )}) = \infty

x \to 0 - lim (\frac{8 sin ( 3 x )}{1 - cos ( 3 x )}) = - \infty

= diverges

\frac{d}{d x} (2 e^{2 x} x + e^{2 x})

\int_{1}^{2} (\frac{x}{y} + \frac{y}{x}) d y

\int_{0}^{3} x 1 + x d x

\frac{d}{d x} (\frac{1}{x ^{2}} - 3 x^{2})

\int (2 + y^{2})^{2} d y

What is the limit as x approaches 0 of (8sin(3x))/(1-cos(3x)) ?
The limit as x approaches 0 of (8sin(3x))/(1-cos(3x)) is diverges