What is the limit as x approaches 9 of (x^2-17x+72)/(x-9) ?

The limit as x approaches 9 of (x^2-17x+72)/(x-9) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 9 of (x^2-17x+72)/(x-9)

x \to 9 lim (\frac{x ^{2} - 17 x + 72}{x - 9})

1

Solution steps

x \to 9 lim (\frac{x ^{2} - 17 x + 72}{x - 9})

Simplify

\frac{x ^{2} - 17 x + 72}{x - 9} : x - 8

= x \to 9 lim (x - 8)

Plug in the value

x = 9

= 9 - 8

Simplify

= 1

(t - 1) (t - 1)

9 e^{x} cos (x)

\frac{s + 3}{( s - 2 ) ( s + 1 )}

x \to 1 lim (2 - x^{2})

\frac{d x}{d y} - sin (x + y) = 0

What is the limit as x approaches 9 of (x^2-17x+72)/(x-9) ?
The limit as x approaches 9 of (x^2-17x+72)/(x-9) is 1