What is the tangent of f(x)=x-2sin(x) ?

The tangent of f(x)=x-2sin(x) is y=(1-2cos(a_{0}))x+2a_{0}cos(a_{0})-2sin(a_{0})

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tangent of f(x)=x-2sin(x)

tangent of

f (x) = x - 2 sin (x)

y = (1 - 2 cos (a_{0})) x + 2 a_{0} cos (a_{0}) - 2 sin (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} - 2 sin (a_{0}))

Find the slope of

f (x) = x - 2 sin (x) : \frac{df ( x )}{d x} = 1 - 2 cos (x)

Compute the slope of

f (x) = x - 2 sin (x)

x = a_{0} : m = 1 - 2 cos (a_{0})

Find the line with slope m=

1 - 2 cos (a_{0})

and passing through

(a_{0}, a_{0} - 2 sin (a_{0})) : y = (1 - 2 cos (a_{0})) x + 2 a_{0} cos (a_{0}) - 2 sin (a_{0})

y = (1 - 2 cos (a_{0})) x + 2 a_{0} cos (a_{0}) - 2 sin (a_{0})

\int_{0}^{2} \frac{x}{x ^{4} + 1} d x

e^{- x^{2}}, 0

\frac{d}{d x} ((x^{4} + 1)^{\frac{1}{2}})

\int 2 z d z

\frac{7 x - 1}{x ^{2} + 9 x}

What is the tangent of f(x)=x-2sin(x) ?
The tangent of f(x)=x-2sin(x) is y=(1-2cos(a_{0}))x+2a_{0}cos(a_{0})-2sin(a_{0})