What is the solution for y^'=(x-y+1)/(x+y-3) ?

The solution for y^'=(x-y+1)/(x+y-3) is y=3-x+sqrt(2x^2-4x+c_{1)+9},y=3-x-sqrt(2x^2-4x+c_{1)+9}

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y^'=(x-y+1)/(x+y-3)

y^{^{'}} = \frac{x - y + 1}{x + y - 3}

y = 3 - x + 2 x^{2} - 4 x + c_{1} + 9, y = 3 - x - 2 x^{2} - 4 x + c_{1} + 9

Solution steps

y^{'} (x) = \frac{x - y + 1}{x + y - 3}

Solve exact ODE:

y = 3 - x + 2 x^{2} - 4 x + c_{1} + 9, y = 3 - x - 2 x^{2} - 4 x + c_{1} + 9

y = 3 - x + 2 x^{2} - 4 x + c_{1} + 9, y = 3 - x - 2 x^{2} - 4 x + c_{1} + 9

f (x) = \frac{2 - ln ( x ^{2} )}{x ^{2}}

n = 1, 3, 5 \sum \infty \frac{1}{n ^{2}}

f (x) = \frac{5 x}{x + 4}, (1, 1)

\frac{d}{d x} (\frac{b}{x ^{2}})

x \to 2 lim (\frac{( 3 x + 2 )}{5 x - 2})^{\frac{( 3 )}{x - 2}}

What is the solution for y^'=(x-y+1)/(x+y-3) ?
The solution for y^'=(x-y+1)/(x+y-3) is y=3-x+sqrt(2x^2-4x+c_{1)+9},y=3-x-sqrt(2x^2-4x+c_{1)+9}