What is the derivative of y=ln(1/x) ?

The derivative of y=ln(1/x) is -1/x

What is the first derivative of y=ln(1/x) ?

The first derivative of y=ln(1/x) is -1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = ln (\frac{1}{x})

- \frac{1}{x}

Solution steps

\frac{d}{d x} (ln (\frac{1}{x}))

Simplify

ln (\frac{1}{x}) : - ln (x)

= \frac{d}{d x} (- ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - \frac{1}{x}

\frac{d}{d x} (\frac{tan ( x )}{1 - sec ( x )})

x e^{x} - e^{x}

\int_{- \infty}^{0} x e^{- x^{2}} d x

\frac{\partial}{\partial x} (x - 3 y)

f (x) = 4 x^{2} - 3 x

What is the derivative of y=ln(1/x) ?
The derivative of y=ln(1/x) is -1/x
What is the first derivative of y=ln(1/x) ?
The first derivative of y=ln(1/x) is -1/x