What is the integral of ((x^2)-3x^2)/(x^1) ?

The integral of ((x^2)-3x^2)/(x^1) is -x^2+C

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integral of ((x^2)-3x^2)/(x^1)

\int \frac{( x ^{2} ) - 3 x ^{2}}{x ^{1}} d x

- x^{2} + C

Solution steps

\int \frac{x ^{2} - 3 x ^{2}}{x ^{1}} d x

Simplify

\frac{x ^{2} - 3 x ^{2}}{x ^{1}} : - 2 x

= \int - 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= - 2 \cdot \frac{x ^{2}}{2}

Simplify

- 2 \cdot \frac{x ^{2}}{2} : - x^{2}

= - x^{2}

Add a constant to the solution

= - x^{2} + C

f (1) = (x^{3} + 2 x + 8)^{3}

\frac{x ^{2}}{x - 3}

\int ln (x - 20) d x

1 + t

x \to 0 + lim (x^{2 \cdot x})

What is the integral of ((x^2)-3x^2)/(x^1) ?
The integral of ((x^2)-3x^2)/(x^1) is -x^2+C