What is the derivative of f(x)= 2/(2x+1) ?

The derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)

What is the first derivative of f(x)= 2/(2x+1) ?

The first derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)

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derivative of

f (x) = \frac{2}{2 x + 1}

- \frac{4}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{2 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 2 (- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2)

Simplify

2 (- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2) : - \frac{4}{( 2 x + 1 ) ^{2}}

= - \frac{4}{( 2 x + 1 ) ^{2}}

\frac{2 z ^{3}}{3} - z

f (t) = e^{2 t s i n (2 t)}

\int_{0}^{1} x (1 - x)^{10} d x

y y^{^{'}} - 21 e^{x} = 0

n = 1 \sum \infty \frac{1}{6 ^{n}}

What is the derivative of f(x)= 2/(2x+1) ?
The derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)
What is the first derivative of f(x)= 2/(2x+1) ?
The first derivative of f(x)= 2/(2x+1) is -4/((2x+1)^2)