What is the integral from 1 to e^2 of 1/x ?

The integral from 1 to e^2 of 1/x is 2

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integral from 1 to e^2 of 1/x

\int_{1}^{e^{2}} \frac{1}{x} d x

2

Solution steps

\int_{1}^{e^{2}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{e^{2}}

Compute the boundaries:

2

= 2

(2, - 3), (4, - 2)

f (x) = \frac{ln ( x )}{x ^{4}}

x \to 1 - lim (2)

\frac{\partial}{\partial y} (ln (x - 9 y))

y^{^{'}} + 3 y = 9 - e^{t}

What is the integral from 1 to e^2 of 1/x ?
The integral from 1 to e^2 of 1/x is 2